自动重启服务的shell脚本代码

复制代码

代码如下:

#!/bin/bash

if [ ! -f /tmp/down_count ];then

echo “0” > /tmp/down_count

fi

curl -I tomcat-host -o “/tmp/status” >/dev/null 2>&1

code=`awk NR==1 {print $2} /tmp/status`

if [ “$[code]” -ge 500 ];then

down=`expr $(cat /tmp/down_count) + 1`

echo “$down” > /tmp/down_count

if [ “$down” -gt 3 ];then

if [ ! -f “/tmp/restart_count” ];then

echo “0” > /tmp/restart_count

fi

restart_count=`expr $(cat /tmp/restart_count) + 1`

echo “$restart_count” > /tmp/restart_count

if [ “$restart_count” -le 2 ];then

echo “tomcat down at `date`” >> /tmp/down_info

/etc/init.d/tomcat6 restart

fi

fi

else

echo “0” > /tmp/down_count

echo “0” > /tmp/restart_count

fi

脚本实现了，当检测网页状态码大于等于500连续出现3次数，自动重启tomcat6，且只连续重启两次。