获取两个日期间隔时间的shell脚本代码

复制代码

代码如下:

#!/bin/sh

# 获取所在季度的第一天，到昨天的日期间隔

# link：www.jb51.net

# date：2013/2/28

day=`date -d “1 days ago ” “+%Y%m%d”`;

year=`expr substr ${day} 1 4`;

month=`expr substr ${day} 5 2`;

s_date=$year”0101″

if [ “$month” == “01” ] || [ “$month” == “02” ] || [ “$month” == “03” ];then

s_date=$year”0101″

elif [ “$month” == “04” ] || [ “$month” == “05” ] || [ “$month” == “06” ];then

s_date=$year”0401″

elif [ “$month” == “07” ] || [ “$month” == “08” ] || [ “$month” == “09” ];then

s_date=$year”0701″

elif [ “$month” == “10” ] || [ “$month” == “11” ] || [ “$month” == “12” ];then

s_date=$year”1001″

fi

e_date=$day

sys_s_data=`date -d “$s_date” +%s`

sys_e_data=`date -d “$e_date” +%s`

interval=`expr $sys_e_data – $sys_s_data`

daycount=`expr $interval / 3600 / 24 + 1`

echo $daycount